Approach to implement a Rest call functionality

[prateek gupta]

Hi All,

I have an admin panel built on Django 2.0.6, MySql 5.7 and Python 3.6.

In this panel I have a field 'PIN' described in models.py like below-
class MerchantStores(models.Model):
store_id = models.AutoField(primary_key=True)
pin = models.CharField(unique=True, max_length=45, blank=True,
null=True)

Currently admin has to fill manually this Pin.

Now, I have to change this PIN text box to a button and on click of this
button a post request will be sent to an api.
This button will be enabled once admin will edit the form (since Pin
generation required store id and a store id will be generated only after
first creating a new store)

The end point of this api will contain the store_id at the end and will
have some required input parameters like api id etc.

Since this api itself saves the new Pin in database , so I don't need to
save this field myself. I just need to show a button and on click this
button make a call to api.

So for this requirement I am going to use Django Rest Framework but before
that I need your suggestion to implement it with a better way.
Please suggest me how can I make a button field instead of text,then how
can I append the store_id to the end point and post my request to the api
successfully?

Thanks,
Prateek Gupta

[Yavin Aalto Arba]

Hi Prateek,

I think your best option is using javascript on the front end - leveraging
an ajax post call.

Post by prateek gupta
Hi All,
I have an admin panel built on Django 2.0.6, MySql 5.7 and Python 3.6.
In this panel I have a field 'PIN' described in models.py like below-
store_id = models.AutoField(primary_key=True)
pin = models.CharField(unique=True, max_length=45, blank=True,
null=True)
Currently admin has to fill manually this Pin.
Now, I have to change this PIN text box to a button and on click of this
button a post request will be sent to an api.
This button will be enabled once admin will edit the form (since Pin
generation required store id and a store id will be generated only after
first creating a new store)
The end point of this api will contain the store_id at the end and will
have some required input parameters like api id etc.
Since this api itself saves the new Pin in database , so I don't need to
save this field myself. I just need to show a button and on click this
button make a call to api.
So for this requirement I am going to use Django Rest Framework but before
that I need your suggestion to implement it with a better way.
Please suggest me how can I make a button field instead of text,then how
can I append the store_id to the end point and post my request to the api
successfully?
Thanks,
Prateek Gupta
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[prateek gupta]

Thanks @Yavin for your suggestion.
I thought I will have to use Django Rest Framework for this functionality,
never thought that from front end I can do that :)

On Tuesday, November 20, 2018 at 5:17:35 PM UTC+5:30, Yavin Aalto Arba

Post by Yavin Aalto Arba
Hi Prateek,
I think your best option is using javascript on the front end - leveraging
an ajax post call.

Post by prateek gupta
Hi All,
I have an admin panel built on Django 2.0.6, MySql 5.7 and Python 3.6.
In this panel I have a field 'PIN' described in models.py like below-
store_id = models.AutoField(primary_key=True)
pin = models.CharField(unique=True, max_length=45, blank=True,
null=True)
Currently admin has to fill manually this Pin.
Now, I have to change this PIN text box to a button and on click of this
button a post request will be sent to an api.
This button will be enabled once admin will edit the form (since Pin
generation required store id and a store id will be generated only after
first creating a new store)
The end point of this api will contain the store_id at the end and will
have some required input parameters like api id etc.
Since this api itself saves the new Pin in database , so I don't need to
save this field myself. I just need to show a button and on click this
button make a call to api.
So for this requirement I am going to use Django Rest Framework but
before that I need your suggestion to implement it with a better way.
Please suggest me how can I make a button field instead of text,then how
can I append the store_id to the end point and post my request to the api
successfully?
Thanks,
Prateek Gupta
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[Yavin Aalto Arba]

Not sure if we're a bit confused on the use case here. REST framework is a
server side platform which can help you implement apis fast, it's a good
idea to use if you don't have an endpoint and want fast CRUD
implementation. As for having a button on the client side - you can use
HTML forms or ajax etc. I think JS\Ajax is the way to go since you can
extract stuff from the document with greater ease and send it away to an
endpoint.

Post by prateek gupta
I thought I will have to use Django Rest Framework for this functionality,
never thought that from front end I can do that :)
On Tuesday, November 20, 2018 at 5:17:35 PM UTC+5:30, Yavin Aalto Arba

Post by Yavin Aalto Arba
Hi Prateek,
I think your best option is using javascript on the front end -
leveraging an ajax post call.

Post by prateek gupta
Hi All,
I have an admin panel built on Django 2.0.6, MySql 5.7 and Python 3.6.
In this panel I have a field 'PIN' described in models.py like below-
store_id = models.AutoField(primary_key=True)
pin = models.CharField(unique=True, max_length=45, blank=True,
null=True)
Currently admin has to fill manually this Pin.
Now, I have to change this PIN text box to a button and on click of this
button a post request will be sent to an api.
This button will be enabled once admin will edit the form (since Pin
generation required store id and a store id will be generated only after
first creating a new store)
The end point of this api will contain the store_id at the end and will
have some required input parameters like api id etc.
Since this api itself saves the new Pin in database , so I don't need to
save this field myself. I just need to show a button and on click this
button make a call to api.
So for this requirement I am going to use Django Rest Framework but
before that I need your suggestion to implement it with a better way.
Please suggest me how can I make a button field instead of text,then
how can I append the store_id to the end point and post my request to the
api successfully?
Thanks,
Prateek Gupta
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[prateek gupta]

Got it, I will try to do the same.

On Tuesday, November 20, 2018 at 6:12:20 PM UTC+5:30, Yavin Aalto Arba

Post by Yavin Aalto Arba
Not sure if we're a bit confused on the use case here. REST framework is a
server side platform which can help you implement apis fast, it's a good
idea to use if you don't have an endpoint and want fast CRUD
implementation. As for having a button on the client side - you can use
HTML forms or ajax etc. I think JS\Ajax is the way to go since you can
extract stuff from the document with greater ease and send it away to an
endpoint.

Post by prateek gupta
I thought I will have to use Django Rest Framework for this
functionality, never thought that from front end I can do that :)
On Tuesday, November 20, 2018 at 5:17:35 PM UTC+5:30, Yavin Aalto Arba

Post by Yavin Aalto Arba
Hi Prateek,
I think your best option is using javascript on the front end -
leveraging an ajax post call.

Post by prateek gupta
Hi All,
I have an admin panel built on Django 2.0.6, MySql 5.7 and Python 3.6.
In this panel I have a field 'PIN' described in models.py like below-
store_id = models.AutoField(primary_key=True)
pin = models.CharField(unique=True, max_length=45, blank=True,
null=True)
Currently admin has to fill manually this Pin.
Now, I have to change this PIN text box to a button and on click of
this button a post request will be sent to an api.
This button will be enabled once admin will edit the form (since Pin
generation required store id and a store id will be generated only after
first creating a new store)
The end point of this api will contain the store_id at the end and will
have some required input parameters like api id etc.
Since this api itself saves the new Pin in database , so I don't need
to save this field myself. I just need to show a button and on click this
button make a call to api.
So for this requirement I am going to use Django Rest Framework but
before that I need your suggestion to implement it with a better way.
Please suggest me how can I make a button field instead of text,then
how can I append the store_id to the end point and post my request to the
api successfully?
Thanks,
Prateek Gupta
--
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[MTS BOUR]

I didn't really understand what you mean, why not use method Post in a
boutton in an Html form ?

Post by prateek gupta
Hi All,
I have an admin panel built on Django 2.0.6, MySql 5.7 and Python 3.6.
In this panel I have a field 'PIN' described in models.py like below-
store_id = models.AutoField(primary_key=True)
pin = models.CharField(unique=True, max_length=45, blank=True,
null=True)
Currently admin has to fill manually this Pin.
Now, I have to change this PIN text box to a button and on click of this
button a post request will be sent to an api.
This button will be enabled once admin will edit the form (since Pin
generation required store id and a store id will be generated only after
first creating a new store)
The end point of this api will contain the store_id at the end and will
have some required input parameters like api id etc.
Since this api itself saves the new Pin in database , so I don't need to
save this field myself. I just need to show a button and on click this
button make a call to api.
So for this requirement I am going to use Django Rest Framework but before
that I need your suggestion to implement it with a better way.
Please suggest me how can I make a button field instead of text,then how
can I append the store_id to the end point and post my request to the api
successfully?
Thanks,
Prateek Gupta
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[prateek gupta]

Hi @MTS S BOUR,
I am not using forms.pr currently. These forms fields are from models.py
only.
That's I w had not thought about html form.

Post by MTS BOUR
I didn't really understand what you mean, why not use method Post in a
boutton in an Html form ?

Post by prateek gupta
Hi All,
I have an admin panel built on Django 2.0.6, MySql 5.7 and Python 3.6.
In this panel I have a field 'PIN' described in models.py like below-
store_id = models.AutoField(primary_key=True)
pin = models.CharField(unique=True, max_length=45, blank=True,
null=True)
Currently admin has to fill manually this Pin.
Now, I have to change this PIN text box to a button and on click of this
button a post request will be sent to an api.
This button will be enabled once admin will edit the form (since Pin
generation required store id and a store id will be generated only after
first creating a new store)
The end point of this api will contain the store_id at the end and will
have some required input parameters like api id etc.
Since this api itself saves the new Pin in database , so I don't need to
save this field myself. I just need to show a button and on click this
button make a call to api.
So for this requirement I am going to use Django Rest Framework but
before that I need your suggestion to implement it with a better way.
Please suggest me how can I make a button field instead of text,then how
can I append the store_id to the end point and post my request to the api
successfully?
Thanks,
Prateek Gupta
--
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