using a foreign key with multiple choices

['Christian' via Django users]

Hello

I need to use a model form to create a new instance of Recette, using
multiple choices list instead of the foreign_key

/class Recette(models.Model)://
//  ......//
//    categoriederecette = models.ForeignKey(Categorie,
on_delete=models.CASCADE) //
/

/class Categorie(models.Model)://
//    SOUPE = 'SP'//
//    DESSERTS ='DS'//
//    PLATUNIQUE ='PU'//
//    LISTE_CHOIX =  ((SOUPE,'Soupe'), (DESSERTS,'Desserts'),
(PLATUNIQUE,'Plat unique'),)//
//   .....//
//    categorierecette = models.CharField(db_column='Categorierecette',
max_length=15, choices=LISTE_CHOIX, blank=True, null=True)  # Field name
made lowercase..../

I use a Modelform/:
/

/class RecettesForm(forms.ModelForm)://
//    categoriederecette = forms.ChoiceField(choices =
Categorie.LISTE_CHOIX)//
////
//    class Meta://
//        model = Recette//
//        fields = (......//,'categoriederecette')/

/
/

The form is displayed correctly,  but cannot be saved. In the test /if
form.is_valid():/  I get a value error -

/ValueError: Cannot assign "'SP'": "Recette.categoriederecette" must be
a "Categorie" instance./

Any help would be greatly appreciated.

[amit pant]

use dict in * LISTE_CHOIX.*

On Tue, Nov 13, 2018 at 6:14 PM 'Christian' via Django users <

Hello
I need to use a model form to create a new instance of Recette, using
multiple choices list instead of the foreign_key
*class Recette(models.Model):*
* ......*
* categoriederecette = models.ForeignKey(Categorie,
on_delete=models.CASCADE) *
*class Categorie(models.Model):*
* SOUPE = 'SP'*
* DESSERTS ='DS'*
* PLATUNIQUE ='PU'*
* LISTE_CHOIX = ((SOUPE,'Soupe'), (DESSERTS,'Desserts'),
(PLATUNIQUE,'Plat unique'),)*
* .....*
* categorierecette = models.CharField(db_column='Categorierecette',
max_length=15, choices=LISTE_CHOIX, blank=True, null=True) # Field name
made lowercase....*
I use a Modelform
* : *
*class RecettesForm(forms.ModelForm):*
* categoriederecette = forms.ChoiceField(choices =
Categorie.LISTE_CHOIX)*
* class Meta:*
* model = Recette*
* fields = (......** ,'categoriederecette')*
The form is displayed correctly, but cannot be saved. In the test *if
form.is_valid():* I get a value error -
* ValueError: Cannot assign "'SP'": "Recette.categoriederecette" must be a
"Categorie" instance.*
Any help would be greatly appreciated.
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[Jani Tiainen]

Well categoriederecette is a foereign key to your Categorie model.

Your models don't make any real sense.

If your categories are fixed you can remove foreign key and add charfield
and definitions directly to Recette model.

If you expect that categories are added, changed, created or deleted
frequently having your current structure is okayish. Just make a name field
in Categorie model as free text.

Hello
I need to use a model form to create a new instance of Recette, using
multiple choices list instead of the foreign_key
*class Recette(models.Model):*
* ......*
* categoriederecette = models.ForeignKey(Categorie,
on_delete=models.CASCADE) *
*class Categorie(models.Model):*
* SOUPE = 'SP'*
* DESSERTS ='DS'*
* PLATUNIQUE ='PU'*
* LISTE_CHOIX = ((SOUPE,'Soupe'), (DESSERTS,'Desserts'),
(PLATUNIQUE,'Plat unique'),)*
* .....*
* categorierecette = models.CharField(db_column='Categorierecette',
max_length=15, choices=LISTE_CHOIX, blank=True, null=True) # Field name
made lowercase....*
I use a Modelform
* : *
*class RecettesForm(forms.ModelForm):*
* categoriederecette = forms.ChoiceField(choices =
Categorie.LISTE_CHOIX)*
* class Meta:*
* model = Recette*
* fields = (......** ,'categoriederecette')*
The form is displayed correctly, but cannot be saved. In the test *if
form.is_valid():* I get a value error -
* ValueError: Cannot assign "'SP'": "Recette.categoriederecette" must be a
"Categorie" instance.*
Any help would be greatly appreciated.
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